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Question

For what value of n, the nth terms of the arithmetic progression 63, 65, 67,... and 3, 10, 17,.. are equal?

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Solution

In the first AP,
a=63d=2Tn=63+(n1)×2=2n+61

In the second AP,
a=3d=7Tn=3+(n1)×7=7n4

Now, 7n4=2n+615n=65n=13


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