Question

For what value of p,

2p - 1,7 and 3p are three consecutive term of an A.P. ?

Answer 1

given$:-$

$2p-1,7,3p$ are in $A.P$

As we know the half of the sum of the $A.P$ is equal to the middle one

$\frac{2p-1+3p}{2}=7$

$5p-1=14$

$5p=14+1$

$5p=15$

$p=3.$