For what value of p, (-4) is a zero of the polynomial $x^{2} - 2 x - (7 p + 3)$ ?

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Solution

If -4 is zero of given polynomial then

$(- 4)^{2} - 2 (- 4) - (7 p + 3) = 0 \Rightarrow 16 + 8 - 7 p - 3 = 0 \Rightarrow 7 p = 21 \Rightarrow p = 3$

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