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Question

For what value of p are 2p+1,13,5p-3 three consecutive terms of an A.P.?

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Solution

2p+1,13, 5p-3, as 13-( 2p+1) gives d this is also equal to (5p-3)-13

so equating it 13-(2p+1)=(5p-3)-13

=13-2p-1=5p-3-13

=12-2p=5p-16

=2p-5p=-16-12

=-7p=-28=

p=4


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