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Question

For what value of p, is (4) a zero of the polynomial p(x)=x22x(7p+3) ?

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Solution

p(x)=x22x(7p+3)

If 4 is a zero of the polynomial,

p(4)=0

(4)22(4)(7p+3)=0

16+8(7p+3)=0

16+8=7p+3

7p=21

p=3

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