Question

For what value of R in the circuit as shown in figure. Current
passing through 4 $\Omega$ resistance will be zero.

• A. $1\Omega$
• B. $2\Omega$
• C. $3\Omega$
• D. $4\Omega$

Answer 1

The correct option is B $2\Omega$

Current through resistance $2\Omega$ is } $I=\frac{9-6}{2}=\frac{3}{2}A$
In the loop ABCDEFA
$-2\times \frac{3}{2}-\frac{3}{2}\times R-3+9=03=\frac{3}{2}RR=2\Omega$