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Question

For what value of x, the matrix A is singular?A=⎡⎢⎣3−x2224−x1−2−4−1−x⎤⎥⎦

A
x=0,2
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B
x=1,2
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C
x=2,3
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D
x=0,3
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Solution

The correct option is D x=0,3
A=3x2224x1241x
If the matrix is singular, its determinant has to be zero.
(3x)[(4x)(1x)+4]2[2(1x)+2]+2[8+2(4x)]=0
(3x)[44x+x+x2+4]2[22x+2]+2[8+82x]=0
(3x)[x23x]+4x4x=0
(3x)x(x3)=0
x=0,3

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