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Question

For what values of a and b does the following pair of linear equations have an infinite number of solutions ?
2x + 3y =7, a (x + y) -b (x + y)= 3a + b - 2

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Solution

Given equation.......
Herewehavetwolinearequation:a1x+b1y+c1=0(1)a2x+b2y+c2=0(2)Now,conditionofinfinitesolution:a1a2=b1b2=c1c2Now,considerfromequation:Fromequ(1)&(2),2x+3y7=0(i)(ab)x+(a+b)y(3a+b2)(ii)Lets,theseequncamparewithabovetwoequn:2x+3y7=0(i)a1=2,b1=3,c1=7(ab)x+(a+b)y(3a+b2)(ii)a2=(ab),b2=(a+b),c1=(3a+b2)Now,givenconndition:a1a2=b1b2=c1c22ab=3a+b=7(3a+b2)findingvalueofa&b,2ab=3a+b=2a+2b=3a3ba=5b(iii)Again,3a+b=7(3a+b2)=9a+3b6=7a+7b=2a4b6=0a2b3=05b2b3=03b=3,b=1putthevalueofbinequ(iii)a=5b,5×1a=5&b=1Nowwegetvalueofa=5&b=1Inthiscasethereareinfinitecases.

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