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Question

For what values of a does the equation x2+2aa23x+4=0 possess equal roots?

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Solution

The equation x2+2aa23x+4=0 possess equal roots if discriminant is zero i.e. D=0
b24ac=0
4a2(a23)4×1×4=0
4a412a216=
4a416a2+4a216=0
4a2(a24)+4(a24)=0
(a24)(a2+1)=0
a=+2,2,+1,1

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