For what values of k can the following numbers form an A.P:2k-1,k+2,2k

3/2

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5/2

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2/5

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2/3

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Solution

The correct option is B
5/2

Since the given numbers are in A.P.

So,

(k + 2) - (2k - 1) = (2k) - (k +2)

Solving we get,

k = 5/ 2

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