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Question

For what values of k can the following numbers form an A.P:2k-1,k+2,2k


A

3/2

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B

2/5

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C

2/3

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D

5/2

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Solution

The correct option is D

5/2


Since the given numbers are in A.P.

So,

(k + 2) - (2k - 1) = (2k) - (k +2)

Solving we get,

k = 5/ 2


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