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Question

For what values of k, the equation kx2-6x-2=0 has real roots?
(a) k-92
(b) k-92
(c) k-2
(d) None of these

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Solution

(b) k -92

It is given that the roots of the equation (kx2 6x 2 = 0) are real. D 0 (b2 4ac) 0 (6)2 4 × k × (2) 0 36 + 8k 0 k 368 k 92

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