Question

For what values of $k$ will $k+9,2k-1$ and $2k+7$ are the consecutive term of an $A.P$?

Answer 1

If $k+9,2k-1$ and $2k+7$ are the consecutive term of an $A.P$ then we'll have,

$2(2k-1)=k+9+2k+7$

or, $4k-2=3k+16$

or, $k=18$.