Question

For what values of 'k' will the equation x² - 2x(k-1) + (k+1)=0 will have equal real roots?

• A. k = 1 or 4
• B. k = 6 or 5
• C. k = 9 or 2
• D. k = 0 or 3

Answer 1

The correct option is D

k = 0 or 3

For the equation to have equal real roots,
$Discriminant=0$
${4(k-1)}^2-4(k+1)=0$
$k^2+1-2k-k-1=0$
$k^2-3k=0$
$k(k-3)=0$
k=0 or k=3