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Question

For what values of m and n following equation has infinitely many solution
3x+4y=12
(m+n)x+2(mn)y=5m1

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Solution

3x+4y=12...(1)
(m+n)x+2(mn)y=5m1....(2)

If given equation has infinityely many solution
then,
aa1=bb1=cc1
3m+n=42(mn)=125m1
3m+n=125m1 & 3m+n=2mn
15m3=12m+12n 3m3n=2m+2n
3m12n=3[m=5n]
m4n=1....(3)
then 5n4n=1
[n=1] & [m=5]
n=1 & m=5 given equation has infinitely many solution.

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