Question

For what values of m does not the equation $m{x}^2-(m+1)x+2m-1=0$ possess no real roots

Answer 1

$m{x}^2-(m+1)x+2m-1=0$

For the equation not have any real roots $D<0$

$b^2-4ac<=$

$(m+1{)}^2-4m(2m-1)<0$

$⟹7m^2-6m-1>0$

$⟹(7m+1)(m-1)>0$

So,$mϵ(-\infty ,\frac{-1}{7})\cup (1,\infty )$