CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

For what values of ‘p’ would the equation x2+2(p1)x+p+5=0 possess at least one positive root?
  1. [ , -5]
  2. [1, ]
  3. [;, -1]
  4. [2, ]


Solution

The correct option is A [ , -5]

For an equation to have positive roots D must be greater than '0'.

Now D from the equation =4(p1)24(1)(p+5)=4p212p16

=4(p23p4)=4(p4)(p+1)

4(p4)(p+1)>0......(1)

So, D is positive in the region (,1) and (4,).

x=b+D2a0
Db2

b2=4(p1)2
p23p4p2+12p
p5..........(2)

Taking intersection of equation (1) and (2), we get -
p lies from (,5].

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image