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Question

For what values of the parameter a such that 51+x+51x,a2,25x+25x are three consecutive terms of an A.P.?

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Solution

As they are in A.P.
a=51+x+51x+25x+25x
So say 5x=t then,
a=5t+5t+t2+1t2
Now, 5t+5t10 [A.M. - G.M. Inequality ]
and t2+1t22 [A.M. - G.M. Inequality ]
So, a12 are the values which a can take.

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