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Question

For what values of x:[1 2 1]12020110202x=0

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Solution

[121]12020110202x=0
[1+4+12+0+00+2+2]02x=0
[624]02x=0
6×0+2×2+4x=0
4+4x=0
x=1
Hence, the answer is 1.


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