CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For what values of x:[1 2 1]12020110202x=0

Open in App
Solution

[121]12020110202x=0
[1+4+12+0+00+2+2]02x=0
[624]02x=0
6×0+2×2+4x=0
4+4x=0
x=1
Hence, the answer is 1.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Matrices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon