For which cell e.m.f. is independent of the concentrations of electrolytes used?

F e | F e O (s) | K O H (a q) | N i O (s) | N i_{2} O_{3} (s) | N i

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P t (H_{2}) | H C l | P t (C l_{2})

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Z n | Z n (N O_{3})_{2} | | C u S O_{4} | C u

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H g, H g C l_{2} | K C l | | A g N O_{3} | A g

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Solution

The correct option is A $F e | F e O (s) | K O H (a q) | N i O (s) | N i_{2} O_{3} (s) | N i$
EMF of cell,
$F e | F e O (s) | K O H (a q) | N i O (s) | N i_{2} O_{3} (s) | N i$
Anode: $F e (s) + 2 O H^{-} \to F e O (s) + H_{2} O (l) + 2 e$
Cathode: $N i_{2} O_{3} (s) + H_{2} O (l) + 2 e \to 2 N i O (s) + 2 O H^{-}$

So according to Nernst equation, emf of cell is
$E_{c e l l} = E_{O P_{F e / F e O}}^{o} - \frac{0.059}{2} l o g_{10} \frac{[H_{2} O]}{[o H^{-}]^{2}} + E_{R P_{N i_{2} O_{3} / N i O}}^{o} + \frac{0.059}{2} l o g_{10} \frac{[H_{2} O]}{[O H^{-}]^{2}}$
$E_{c e l l} = E_{O P_{F e / F e O}}^{o} + E_{R P_{N i_{2} O_{3} / N i O}}^{o}$ which is independent of conc. of ions in solution.

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Similar questions

Q. The Edison storage cell is represented as:

F e (s) | F e O (s) | K O H (a q .) | N i_{2} O_{3} (s) | N i (s)

The half-cell reactions are:

N i_{2} O_{3} (s) + H_{2} O (l) + 2 e^{-} \to 2 N i O (s) + 2 O H^{-}; E^{\circ} + 0.40

F e O (s) + H_{2} O (l) + 2 e^{-} \to F e (s) + 2 O H^{-}; E^{\circ} = - 0.87

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(b) What is the emf of the cell? How does it depend on concentration of

K O H

?
(c) What is the maximum amount of energy that can obtained from one mole of

N i_{2} O_{3}

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The half-cell reactions are:
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