Question

For which equation(s) is $x=3$ a solution?
(I) $2x-5+3x=10$ (II) $\frac{-x+7}{2}=2$
(III) $4x-11=17$ (IV) $9=-(x-1)+11$

• A. I only
• B. I and II
• C. I,II and III
• D. I,II and IV

Answer 1

The correct option is D I,II and IV

(I) $2x-5+3x=10$

$⟹5x-5=10$

$⟹5x=10+5=15$

$⟹x=\frac{15}{5}=3$

(II)$\frac{(-x+7)}{2}=2$

$-x+7=2\times 2$

$-x=4-7=-3$

$x=3$

(III)$4x-11=17$

$⟹4x=17+11$

$⟹x=\frac{28}{4}=7$

(IV) $9=-(x-1)+11$

$9+(x-1)=11$

$x+8=11$

$x=11-8=3$

Answer :D