Question

For which equation(s) is $x=3$ a solution?
(I) $2x-5+3x=10$ (II) $\frac{-x+7}{2}=2$ (III) $4x-11=17$ (IV) $9=-(x-1)+1$

• A. Only I
• B. I and II
• C. I, II and III
• D. I, II and IV

Answer 1

Answer: (B)

I and II

(I) $2x-5+3x=10$

In LHS put value of $x=3$, we get

$2\times 3-5+3\times 3=$

$=6-5+9=10$

Then LHS =RHS

(II) $\frac{-x+7}{2}=2$

In LHS put value of $x=3,$ we get

$\frac{-3+7}{2}=\frac{4}{2}=2$

Then LHS =RHS

(III) $4x-11=17$

In LHS put value of $x=3$ we get

$4\times 3-11=12-11=1$

$LHS\ne RHS$

(IV) $-9=-(x-1)+1$

In RHS put value of $x=3,$ we get

$-(3-1)+1=-2+1=-1$

$LHS\ne RHS$

Then I and II are answer