Question

For which of the following compound, the formula $\alpha ={\lambda }_v/{\lambda }_{\infty }$ does not hold good?

• A. $C{H}_{3}COOH$
• B. $HCl$
• C. $HCl{O}_4$
• D. $C{H}_{3}N{H}_2$

Answer 1

Answer: (B), (C)

$HCl{O}_4$
$HCl$

This formula $\alpha ={\lambda }_v/{\lambda }_{\infty }$ holds good for weak electrolytes such as $C{H}_{3}COOH$ and $C{H}_{3}N{H}_2$.

However, the formula $\alpha ={\lambda }_v/{\lambda }_{\infty }$ does not hold good for strong electrolytes such as $HCl$ and $HCl{O}_4$

Hence, option B and C are correct.