Question

For which of the following options has m = 0 for all orbitals?

• A. $2s,2p_x,3d_{xy}$
• B. $3s,2p_z,3d_{z^2}$
• C. $2s,2p_z,3d_{x^2-y^2}$
• D. $3s,3p_x,3d_{yz}$

Answer 1

The correct option is B $3s,2p_z,3d_{z^2}$

For, $35,2p_z,3d_{z^2}$

$n=3,l=0,ml=0,\Rightarrow 35$

$\to$ For $2p_z,n=2,l=1,ml=-1,0,1$

For $p_z,ml=0$

$\to$ For $3d_{z^2},n=3,l=2$

$ml=-2,-1,0,1,2$ for $d_{z^2}7ml=0$

Hence, option (B) is Correct