For which of the following process -S is - 0-

The correct option is A MgCO_3(s)→ MgO(s)+CO_2(g) Solution: (A) #160; MgCO_3_( s )⟶MgO_( s ) + CO_2_( g ) The entropy of a system increases wheneve ...

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Byju's Answer

Standard XII

Chemistry

Heat of Reaction

For which of ...

Question

For which of the following process $Δ S$ is $> 0$ ?

M g {C O}_{3} (s) \to M g O (s) + {C O}_{2} (g)

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2 I (g) \to I_{2} (g)

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{N a}^{+} (g) + C l (g) \to N a C l (s)

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H_{2} O (l) \to H_{2} O (s)

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Solution

The correct option is A $M g {C O}_{3} (s) \to M g O (s) + {C O}_{2} (g)$
Solution:- (A) ${M g C O_{3}}_{(s)} ⟶ {M g O}_{(s)} + {C O_{2}}_{(g)}$
The entropy of a system increases whenever its particles have more freedom of motion.
Thus, the entropy increases whenever you have more moles of gaseous products than of reactants and whenever you have more product particles in solution than you have of reactant particles.
Hence among the given reactions, the entropy increases in-
${M g C O_{3}}_{(s)} ⟶ {M g O}_{(s)} + {C O_{2}}_{(g)}$
Since the reactant side has no gaseous particle while the product side has $1$ gaseous particle.
Hence the entropy increases and $Δ S$ will be greater than $0$ .

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Δ S

for the reaction

M g C O_{3} (s) \to M g O (s) + C O_{2} (g)

will be:

Δ S

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M g C O_{3} (s) \to M g O (s) + C O_{2} (g)

will be:

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for the reaction,

M g C O_{3} (s) \to M g O (s) + C O_{2} (g)

will be:

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, which of the following expression is correct?

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For which of the following process ΔS is >0?

For which of the following process $Δ S$ is $> 0$ ?