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Bond Order and Enthalpy

For which of ...

Question

For which of the following reaction, will $△$ H be equal to $△$ E?

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)

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H_{2} (g) + I_{2} (g) \to 2 H I (g)

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2 {N O}_{2} (g) \to N_{2} O_{4} (g)

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2 {S O}_{3} (g) \to 2 {S O}_{2} (g) + O_{2} (g)

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Solution

The correct option is A $H_{2} (g) + I_{2} (g) \to 2 H I (g)$
$Δ H = Δ E + Δ n_{g a s} R T$
$∴ Δ H = Δ E$ if $Δ n_{g a s} = 0$
$A \to Δ n_{g a s} = 1 - 1 - \frac{1}{2} = (- 1 / 2)$
$B \to Δ n_{g a s} = 2 - 1 - 1 = 0$
$C \to Δ n_{g a s} = 1 - 2 = (- 1)$
$D \to Δ n_{g a s} = 2 + 1 - 2 = 1$

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