For which of the following represents the expression for three/fourth life of reaction ?

\frac{k}{2.303} l o g 4 / 3

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\frac{2.303}{k} l o g 3 / 4

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\frac{2.303}{k} l o g 4

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\frac{2.303}{k} l o g 3

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Solution

The correct option is C $\frac{2.303}{k} l o g 4$
As we know, for a first order reaction,

$t = \frac{2.303}{K} l o g \frac{a}{(a - x)}$

If $t = t_{3 / 4}; x = 3 a / 4$

$∴ t_{3 / 4} = \frac{2.303}{K} l o g \frac{a}{a - 3 a / 4}$ $= \frac{2.303}{K} l o g (4)$

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For which of the following represents the expression for three/fourth life of reaction ?

The correct option is C 2.303klog4As we know, for a first order reaction,t=2.303Kloga(a−x)If t=t3/4;x=3a/4∴t3/4=2.303Klogaa−3a/4 =2.303Klog(4)

The correct option is C $\frac{2.303}{k} l o g 4$
As we know, for a first order reaction,

$t = \frac{2.303}{K} l o g \frac{a}{(a - x)}$

If $t = t_{3 / 4}; x = 3 a / 4$

$∴ t_{3 / 4} = \frac{2.303}{K} l o g \frac{a}{a - 3 a / 4}$ $= \frac{2.303}{K} l o g (4)$