For which value of x, the functionf(x)=x2–2x is decreasing
x>1
x>2
x<1
x<2
Find the value of x:
Given, f(x)=x2–2x
⇒ f'(x)=2x–2
According to the question,
f(x) should be decreasing
⇒ f'(x)<0
⇒2x-2<0
⇒ 2x<2
∴x<1
Hence, Option ‘C’ is Correct.