For x = 1, y = 3, u = -5, v = 6 the point (x+y, u+v) lies in the quadrant .

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Solution

The correct option is A 1
Abscissa is x + y = 1 + 3 = 4

Ordinate is u + v = -5 + 6 = 1

The point is (4,1).

Since both coordinates of the point are positive
$∴$ The point lies in quadrant I.

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For x = 3, y = 2, u = -9, v = 13 the point (x+y, u+v) lies in which quadrant?

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(x \times y, u \times v)

Prove that if then . Will this be true if we use some other numbers instead of 2, 5, 4 and 6?

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x^{2} + y^{2} - 7 x - 9 y + c = 0

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