For x=2 and y=-3, verify the following .
x-y2=x2-2xy+y2
We have x-y2=x2-2xy+y2
substituting x=2 and y=-3 we get
x-y2=x2-2xy+y22--32=22-2×2×-3+-322+32=4+12+952=13+1225=25LHS=RHS
Since, LHS and RHS both are same .
Hence, it's verified .
Find the following products and verify the result for x = -1, y = - 2:
(3x−5y)(x+y)
x2-y2=(x+y)(x-y)
Verify
x-(-y)=x+yIfx=5andy=3
(-x)+(-y)=-(x+y)ifx=5andy=3