wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For x=2 and y=-3, verify the following .

x-y2=x2-2xy+y2


Open in App
Solution

We have x-y2=x2-2xy+y2

substituting x=2 and y=-3 we get

x-y2=x2-2xy+y22--32=22-2×2×-3+-322+32=4+12+952=13+1225=25LHS=RHS

Since, LHS and RHS both are same .

Hence, it's verified .


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General and Particular Solutions of a DE
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon