For x=2 and y=-3, verify the following .
x2-y2=(x+y)(x-y)
We have x2-y2=(x+y)(x-y)
substituting x=2 and y=-3 we get
22--32=(2+-3)(2--3)4-9=(2-3)(2+3)-5=-15-5=-5LHS=RHS
Since, LHS and RHS both are same .
Hence, it's verified .
x-y2=x2-2xy+y2
Verify
x-(-y)=x+yIfx=5andy=3
(-x)+(-y)=-(x+y)ifx=5andy=3
Verify x^3 × y^3 =(x+y)(x^2-xy + y^3)