For xϵ[0,12], f(x)=tan(sin−1(x√2+√1−x22)−sin−1x) is
discontinuous at one point
discontinuous at two point
continuous throughout
discontinuous at infinite points
sin−1(x√2+√1−x22)=sin−1(x√1−(1√2)2+1√2√1−x2)
=sin−11√2
⇒f(x)=tan(sin−11√2)=tanπ4
So, f(x)=1
Hence, the function is continuous throughout.
Let f(x) be defined in [–2,2] by f(x)={max{√4−x2,√1+x2}−2≤x≤0min{√4−x2,√1+x2}0<x≤2 . Then f(x) is