Question

Force acting on a particle constrained to move along $x-$ axis is $F=(x-4)$. Here, $F$ is in newton and $x$ is in meter. Find the equilibrium position.

• A. $x=4m,$
• B. $x=2$
• C. $x=-3$
• D. $x=1$

Answer 1

The correct option is A $x=4m,$

$F=(x-4)$
$F=0$ at $x=4m$
When $x>4m,F=+ve$
When displaced from $x=4m$ (towards positive direction) force also acts in the same direction. Therefore equilibrium is unstable.