Force acting on a particle varies with displacement as shown in figure. The workdone by this force on the particle from x=−8mtox=+8m
A
60J
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B
−60J
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C
100J
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D
−100J
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Solution
The correct option is A60J Work done (w) = Area under F - x graph = Area of I + Area II + Area of III+ Area of IV =12×(4)×(−10)+12×(4)×(10)+(4)×10+12×(4)×10=32×4×10=60 J