Question

Force acting on a particle varies with $x$ as shown in figure. Calculate the work done by the force as the particle moves from $x=0$ to $x=6.0\text{m}$.

• A. $15\text{J}$
• B. $20\text{J}$
• C. $25\text{J}$
• D. $30\text{J}$

Answer 1

The correct option is C $25\text{J}$

The work done by the force is equal to the area under the curve from
$x=0$ to $x=6.0\text{m}$.

The area of Rectangle is given by,

$A_1=4\times 5=20$ $\text{N-m}$

The area of triangle is given by,

$A_2=\frac{1}{2}\times 2\times 5=5$ $\text{N-m}$

So, the total work done $=$ $A_1+A_2$

$=25\text{N-m}$ $=25\text{J}$

Why this Qiestion ? Note : The area enclosed by the $F-x$ graph represents the work done by the force.