Question

Force acting upon a charged particle kept between the plates of a charged condenser is F.If one of the plates of the condenser is removed,force acting on the same particle will become

• A. zero
• B. $\frac{F}{2}$
• C. F
• D. 2F

Answer 1

Answer: (B)

$\frac{F}{2}$

The Electric field between oppositely charged plates of a capacitor is twice that due to one plate .Hence ,when one plate is removed,the electric field becomes half and hence ,the force reduces by half ,i.e becomes F/2