Force applied by water stream depends on density of water - velocity of the stream v and cross sectional area of the stream A- The expression of the force should be -

The correct option is B ρ A #160; v^2 Force is rate of change in momentum: F= dP dt #160;(P is momentum ) F= dm dt v #160 ...

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Standard XII

Chemistry

Longest Chain Rule

Force applied...

Question

Force applied by water stream depends on density of water $(ρ)$ velocity of the stream $(v)$ and cross sectional area of the stream $(A)$ . The expression of the force should be :

ρ

A v

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ρ A

v^{2}

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ρ^{2} A v

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ρ^{4} 2 v

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Solution

The correct option is B $ρ A$ $v^{2}$
Force is rate of change in momentum:

$F = \frac{d P}{d t} (P$ is momentum $)$

$F = \frac{d m}{d t} v$

$= \frac{d (ρ A l)}{d t} v (m = ρ A l) = \frac{d l}{d t} ρ A v (\frac{d l}{d t} = v) = ρ A v^{2}$

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Force applied by water stream depends on density of water (ρ) velocity of the stream (v) and cross sectional area of the stream (A). The expression of the force should be :

The correct option is B ρA v2Force is rate of change in momentum:F=dPdt(P is momentum)F=dmdtv =d(ρAl)dtv(m=ρAl)=dldtρAv(dldt=v)=ρAv2

Force applied by water stream depends on density of water $(ρ)$ velocity of the stream $(v)$ and cross sectional area of the stream $(A)$ . The expression of the force should be :

The correct option is B $ρ A$ $v^{2}$
Force is rate of change in momentum:

$F = \frac{d P}{d t} (P$ is momentum $)$

$F = \frac{d m}{d t} v$

$= \frac{d (ρ A l)}{d t} v (m = ρ A l) = \frac{d l}{d t} ρ A v (\frac{d l}{d t} = v) = ρ A v^{2}$