Force between two charges separated by a certain distance in air is F. If each charge is doubled and the distance between them is also doubled, force would be

F

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2 F

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\frac{F}{2}

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3 F

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Solution

The correct option is A $F$
$\begin{matrix} F = \frac{K Q^{2}}{r^{2}} F^{'} = \frac{4 K a^{2}}{4 r^{2}} = F ∴ F^{'} = F \end{matrix}$
Hence,
option $A$ is correct answer.

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Force between two charges separated by a certain distance in air is F. If each charge is doubled and the distance between them is also doubled, force would be

The correct option is A FF=KQ2r2F′=4Ka24r2=F∴F′=FHence,option A is correct answer.

The correct option is A $F$
$\begin{matrix} F = \frac{K Q^{2}}{r^{2}} F^{'} = \frac{4 K a^{2}}{4 r^{2}} = F ∴ F^{'} = F \end{matrix}$
Hence,
option $A$ is correct answer.