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Question

Force between two charges separated by a certain distance in air is F. If each charge is doubled and the distance between them is also doubled, force would be


A
F
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B
2F
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C
F2
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D
3F
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Solution

The correct option is A $$F$$
$$\begin{array}{l} F=\frac { { K{ Q^{ 2 } } } }{ { { r^{ 2 } } } }  \\ F'=\frac { { 4K{ a^{ 2 } } } }{ { 4{ r^{ 2 } } } } =F \\ \therefore F'=F \end{array}$$
Hence,
option $$A$$ is correct answer.

Physics

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