Question

# Force between two charges separated by a certain distance in air is F. If each charge is doubled and the distance between them is also doubled, force would be

A
F
B
2F
C
F2
D
3F

Solution

## The correct option is A $$F$$$$\begin{array}{l} F=\frac { { K{ Q^{ 2 } } } }{ { { r^{ 2 } } } } \\ F'=\frac { { 4K{ a^{ 2 } } } }{ { 4{ r^{ 2 } } } } =F \\ \therefore F'=F \end{array}$$Hence,option $$A$$ is correct answer.Physics

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