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Question

# Force constant of a weightless spring is 16 N/m. A body of mass 1.0 kg suspended from it is pulled down through 5 cm from its mean position and then released. The maximum kinetic energy of the body will be

A
2×102 J
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B
4×102 J
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C
8×102 J
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D
16×102 J
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Solution

## The correct option is A 2×10−2 JLet us assume , spring- mass system is initially in equilibrium at x=0. Let this point be the reference point about which the body executes SHM. Given, Mass of the body m=1.0 kg Elongation of spring/Amplitude of SHM A=5 cm Maximum kinetic energy of the body attached to the spring is given by Kmax=12kA2 =12×16×(5×10−2)2=2×10−2 J Thus, option (a) is the correct answer.

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