Question

Force experienced by charge ${}^{\prime }{q}^{\prime }$ moving with velocity ${}^{\prime }{v}^{\prime }$ in a magnetic field ${}^{\prime }{B}^{\prime }$ is given by $F=qvB$. Find the dimension of magnetic field.

Answer 1

The expression relating magnetic force with magnetic field is:

$F=qvB$

$\Rightarrow B=\frac{F}{qv}$

So, dimensions of B are:

$\frac{\left[ML{T}^{-2}\right]}{\left[AT\right]\left[L{T}^{-1}\right]}$

$\Rightarrow \left[M{T}^{-2}{A}^{-1}\right]$