Force F is applied horizontally at the vertex of equilateral triangular wedge of side l and mass m placed on the ground. Friction is considered to be absent everywhere. The minimum value of F required to topple the wedge is
A
mg2
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B
√3mg2
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C
mg√3
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D
mg
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Solution
The correct option is B√3mg2 By force balance on the wedgeN=mg−−(i)Before it topples net torque at centre of mass (point P) is zero. When it is about to topple the torque due to force F is balanced by the torque due to Normal reaction acting at point C. ∴N×l2=F×l√3−−(ii) By using equ (i) and (ii) we get F=√3mg2