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Work Done When Path Is Not Straight

Force F on a ...

Question

Force F on a particle moving in a straight line varies with displacement d as shown in the figure. The work done on the particle during its displacement of 12 m is:

21J

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13J

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18J

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Solution

The correct option is C
13J

Work done = Area under F-d graph
$= 2 \times (7 - 3) + \frac{1}{2} \times 2 \times (12 - 7)$
$= 2 \times 4 + 5 = 13$ Joule

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