Question

Force $F$ on a particle moving in a straight line varies with distance $d$ as shown in the figure
The work done on the particle during its displacement of $12\text{m}$ is

• A. $18\text{J}$
• B. $21\text{J}$
• C. $26\text{J}$
• D. $13\text{J}$

Answer 1

The correct option is D $13\text{J}$

Total work done= $W={\int }_3^{12}\overrightarrow{F}.d\overrightarrow{x}$
also, $W_{trap}=\frac{1}{2}\times h\times$ sum of parallel sides
$W=\frac{1}{2}\times (2-0)\times (9+4)W=13J$