Force is applied on an object of mass $2 k g$ at rest on a frictionless horizontal surface as indicated on the graph. After $1$ second, the speed (in $m s^{- 1})$ of the object is

7.5

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12.5

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15

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25

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Solution

The correct option is A $7.5$
As we know that Force $F = \frac{d P}{d t}$ , $P$ is momentum so $d P = F d t$ where $d P$ is change in momentum due to force $F$
In other words the momentum imparted by force will be given by the $a r e a$ under the $F - t$ graph
so $Δ P = a r e a = smaller rectangle + larger vertical rectangle = 10 N \times (0.5 - 0) s + 20 N \times (1.0 - 0.5) s$
or $Δ P = 15 N s$
so the velocity change is $Δ v = \frac{15 N s}{m a s s} = 7.5 m / s$
as the mass started from mass so new velocity will be $7.5 m / s$

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Force is applied on an object of mass 2 kg at rest on a frictionless horizontal surface as indicated on the graph. After 1 second, the speed (in ms−1) of the object is

Force is applied on an object of mass $2 k g$ at rest on a frictionless horizontal surface as indicated on the graph. After $1$ second, the speed (in $m s^{- 1})$ of the object is