Force is required to lift a body from the nbsp-ground to a height h and work is measured nbsp-as the product of force and magnitude of nbsp-displacement- nbsp-a- Name the energy possessed by the nbsp-body at maximum height- Write an nbsp-equation for it- nbsp-b- A man of mass 60 kg carries a nbsp-stone of mass 20 kg to the top of a nbsp-multi-storeyed building nbsp- nbsp- of height nbsp-50m- Calculate the total energy nbsp-spent by him- -9-8m-s2-

A). #160;the #160;energy #160;possesed #160;is #160;gravitational #160;potential #160;enrgy #160;.eqn #160;for #160;PE #160;for #160;mas ...

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Byju's Answer

Standard XII

Physics

Work by Multiple Forces

Force is requ...

Question

Force is required to lift a body from the ground to a height h and work is measured
as the product of force and magnitude of displacement.
a) Name the energy possessed by the body at maximum height. Write an equation for it.
b) A man of mass 60 kg carries a stone of mass 20 kg to the top of a multi-storeyed building of height 50m. Calculate the total energy spent by him? (9.8m/s2)

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Solution

$a) . t h e e n e r g y p o s s e s e d i s g r a v i t a t i o n a l p o t e n t i a l e n r g y . e q n f o r P E f o r m a s s m a t h e i g h t h U = m g h b) . t o t a l m a s s M = 60 + 20 = 80 k g . h = 50 m . w o r k d o n e b y t h e m a n = m g h = 80 * 9.8 * 50 = 39200 J R e g a r d s$

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a). the energy possesed is gravitational potential enrgy .eqn for PE for mass m at height h U=mghb). total mass M=60+20=80 kg .h=50m.work done by the man =mgh=80*9.8*50=39200JRegards

$a) . t h e e n e r g y p o s s e s e d i s g r a v i t a t i o n a l p o t e n t i a l e n r g y . e q n f o r P E f o r m a s s m a t h e i g h t h U = m g h b) . t o t a l m a s s M = 60 + 20 = 80 k g . h = 50 m . w o r k d o n e b y t h e m a n = m g h = 80 * 9.8 * 50 = 39200 J R e g a r d s$