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Standard XIII

Physics

Coulomb's Law - Mathematical Form

Force of attr...

Question

Force of attraction between two point charges Q and – Q separated by d metre is $F_{e}$ . When these charges are placed on two identical spheres of radius R=0.3 d whose centres are d metre apart, the force of attraction between them is

Greater than

F_{e}

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Equal to

F_{e}

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Less than

F_{e}

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Less than

F_{e}

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Solution

The correct option is A Greater than $F_{e}$
Separation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.

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Force of attraction between two point charges Q and – Q separated by d metre is Fe . When these charges are placed on two identical spheres of radius R=0.3 d whose centres are d metre apart, the force of attraction between them is

The correct option is A Greater than FeSeparation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.

Force of attraction between two point charges Q and – Q separated by d metre is $F_{e}$ . When these charges are placed on two identical spheres of radius R=0.3 d whose centres are d metre apart, the force of attraction between them is

The correct option is A Greater than $F_{e}$
Separation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.