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Standard XII

Physics

Elasticity

Force require...

Question

Force required to increase the length of a wire of area of cross-section $A$ by one percent is (Given young's modulus $= Y$ )

A Y

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A Y / 10

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A Y / 100

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A Y / 1000

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Solution

The correct option is B $A Y / 100$
Young's modulus= tensile stress / tensile strain
$Y = \frac{F}{A} / \frac{l}{L}$
$Y = F L / A l$

$F = Y A l / L$
$\frac{l}{L} = \frac{1}{100}$

$F = \frac{A Y}{100}$

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Force required to increase the length of a wire of area of cross-section A by one percent is (Given young's modulus=Y)

The correct option is B AY/100Young's modulus= tensile stress / tensile strainY=FA/lLY=FL/AlF=YAl/L lL=1100F=AY100

Force required to increase the length of a wire of area of cross-section $A$ by one percent is (Given young's modulus $= Y$ )

The correct option is B $A Y / 100$
Young's modulus= tensile stress / tensile strain
$Y = \frac{F}{A} / \frac{l}{L}$
$Y = F L / A l$

$F = Y A l / L$
$\frac{l}{L} = \frac{1}{100}$

$F = \frac{A Y}{100}$