Forces F1 and F2 are acting on a body in opposite directions. The body displaces by 's' metres in the direction of force F2. What is the total work done on the body?
400 J
Given: Since the body displaces in the direction of force F1, force F1 is greater than force F2 and displacement 's' is in the direction of force F2 (given).
Work done = Force × Displacement
⇒ Total work done = (F1 − F2) × s